August 27, 2016 - algorithm

380. Insert Delete GetRandom O(1)

Design a data structure that supports all following operations in average O(1) time.

Note: Duplicate elements are allowed.

insert(val): Inserts an item val to the collection. remove(val): Removes an item val from the collection if present. getRandom: Returns a random element from current collection of elements. The probability of each element being returned is linearly related to the number of same value the collection contains.

Example:

Init an empty collection.
RandomizedCollection collection = new RandomizedCollection();

// Inserts 1 to the collection. Returns true as the collection did not contain 1.
collection.insert(1);

// Inserts another 1 to the collection. Returns false as the collection contained 1. Collection now contains [1,1].
collection.insert(1);

// Inserts 2 to the collection, returns true. Collection now contains [1,1,2].
collection.insert(2);

// getRandom should return 1 with the probability 2/3, and returns 2 with the probability 1/3.
collection.getRandom();

// Removes 1 from the collection, returns true. Collection now contains [1,2].
collection.remove(1);

// getRandom should return 1 and 2 both equally likely.
collection.getRandom();

1. Analyse

Same principle as 380. Insert Delete GetRandom O(1). But this time we store a struct into unordered_map.

AC Code

class RandomizedCollection {
public:
    vector<int> position;
    unordered_map<int, unordered_set<int> > mp;
    /** Initialize your data structure here. */
    RandomizedCollection() {
        srand(time(NULL));
    }
    
    /** Inserts a value to the collection. Returns true if the collection did not already contain the specified element. */
    bool insert(int val) {
        mp[val].insert( position.size() );
        position.push_back(val);
        return 1 == mp[val].size();
    }
    
    /** Removes a value from the collection. Returns true if the collection contained the specified element. */
    bool remove(int val) {
        if( 0 == mp.count(val) )    return false;

        int index = *mp[val].begin();
        int last_item = position.back();

        position[ index ] = last_item;              //move the last item 
        mp[val].erase( index );                     //remove val index
        mp[last_item].insert( index );              //add last_item index
        mp[last_item].erase( position.size()-1 );   //remove last_item index
        position.pop_back();                        //remove the last item

        if( mp[val].empty() )
            mp.erase( val );                        //remove val index 
        return true;
    }
    
    /** Get a random element from the collection. */
    int getRandom() {
        return position[ rand() % position.size() ];
    }
}; 

Reference

  1. share my 116ms c++ solution. zoharlee.